This file is part of a program based on the Bio 4835 Biostatistics class taught
at
Daniel, W. W. 1999. Biostatistics: a foundation for analysis in the
health sciences.
The file follows this text very closely and readers are encouraged to consult
the text for further information.
F) Confidence interval for the ratio of variances of two
normally distributed populations
A way to compare the variances of two normally distributed populations is to
use the variance ratio,
/
. The variance ratio is used, among other things, as the
test statistic for analysis of variance (ANOVA). If the two variances are
equal, then V. R. = 1.
Sampling distribution
The sampling distribution of (
/
)/(
/
) is used.
Since the population variances are usually not known, the sample variances are
used. The assumptions are that
and i
are computed from
independent samples of size
and
, respectively, drawn
from two normally distributed populations. If the assumptions are
met, (
/
)/(
/
) follows a
distribution known as the F distribution with two values used for
degrees of freedom.
Degrees of freedom
The F distribution uses two values for degrees of freedom. The
numerator degrees of freedom is the value of
-1 which is
used in calculating
.
The denominator degrees of freedom is the value of
-1 which is
used in calculating
.
Reading F tables
F tables come in denominations based on
which
are
,
,
,
and
with one tail. For two tail intervals, the lower boundary,
, must be calculated to give
values of
,
and
.
Confidence interval for
/
The distribution (
/
)/(
/
) is used to
establish the 100(1-
) percent confidence interval for
/
. The
staring point is
From this relation, it can be shown that the 100(1-
) percent
confidence interval for
/
is
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Example
Among 11 patients in a certain study, the standard deviation of the property of
interest was 5.8. In another group of 4 patients, the standard deviation
was 3.4. We wish to construct a 95 percent confidence interval for the
ratio of the variances of these two populations.
(1) Given
= 11
=
= 33.64
= 4
=
= 11.56
= .05
10, 3 = 14.42
= 1/
3, 10 = 1/4.83 =
.20704
(2) Calculations
Calculation of the 95% confidence interval for
/
